Question

The electric flux emerging through the closed surface $S_1$ shown in figure which intersects the spherical conductor $S,$ due to the presence of a positive charge very near to conductor is:

• A. Positive
• B. Negative
• C. Zero
• D. None of the above

Answer 1

The correct option is A Positive

As you see, due to $+q$ charge a $-ve$ charge will induce on the surface of conductor which is near to the charge.

But there will be a positive charge also induced on the other side and our gaussion surface will thus have positive charge enclosed in it.

$\Rightarrow \varphi =\frac{+q}{{\epsilon }_0}$ {positive flux}

$\therefore$ Option A is the correct answer.