The electric flux entering a closed surface is $2000 V m$ and the flux coming out of the closed surface is $1000 V m$ . Then, the net charge enclosed inside the surface is :

z e r o

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+ 8.85 n C

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- 8.85 n C

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- 17.7 n C

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Solution

The correct option is D $- 8.85 n C$
According to Gauss's law:
flux out - flux in = $\frac{q_{e n c l o s e d}}{ϵ_{0}}$
so,
$1000 V m - 2000 V m = \frac{q_{e n c l o s e d}}{ϵ_{0}}$
$⟹ q_{e n c l o s e d} = - 1000 V m \times 8.85 \times 10^{- 12}$ $F m^{- 1}$
$⟹ q_{e n c l o s e d} = - 8.85 n C$

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The electric flux entering a closed surface is 2000Vm and the flux coming out of the closed surface is 1000Vm. Then, the net charge enclosed inside the surface is :

The correct option is D −8.85nCAccording to Gauss's law:flux out - flux in = qenclosedϵ0so,1000Vm−2000Vm=qenclosedϵ0⟹qenclosed=−1000Vm×8.85×10−12 Fm−1⟹qenclosed=−8.85nC

The electric flux entering a closed surface is $2000 V m$ and the flux coming out of the closed surface is $1000 V m$ . Then, the net charge enclosed inside the surface is :