The electric flux over a sphere of radius $1 m$ is $ϕ$ . If radius of the sphere were doubled without changing the charge enclosed, electric flux would become

2 ϕ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

ϕ / 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

ϕ / 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

ϕ

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $ϕ$
We know gauss law $ϕ = \frac{Q_{e n c l o s e}}{ϵ_{o}}$
$∴$ as q enclosed is not changing $ϕ$ also remains same

Suggest Corrections

Similar questions

A sphere of radius $1 m$ encloses a charge of $5 μ C$ . Another charge of $- 5 μ C$ is placed inside the sphere. The net electric flux would be :

l

ϕ

2 l

ϕ

ϕ

The electric flux from a cube of edge $l$ is $ϕ$ . Its value if edge of cube is made $2 l$ and charge enclosed is halved is

Join BYJU'S Learning Program