The electric force experienced by a charge of 1-0 - 10-6 C is 1-5 - 10-3 N- Find the magnitude of the electric field at the position of the charge-

Given: Magnitude of the charges, q = nbsp; 1.0 times; 10 minus;6 C Electric force, F = 1.5 times; 10 minus;3 N We know that F = qE #8658;E=Fq=1.5 ...

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Standard XII

Physics

Coulomb's Law - Mathematical Form

The electric ...

Question

The electric force experienced by a charge of 1.0 × 10⁻⁶ C is 1.5 × 10⁻³ N. Find the magnitude of the electric field at the position of the charge.

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Solution

Given:
Magnitude of the charges, q = 1.0 × 10⁻⁶ C
Electric force, F = 1.5 × 10⁻³ N
We know that F = qE
$\Rightarrow E = \frac{F}{q} = \frac{1.5 \times 10^{- 3}}{1.0 \times 10^{- 6}} = 1.5 \times 10^{3} N / C$

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The electric force experienced by a charge of 1.0 × 10−6 C is 1.5 × 10−3 N. Find the magnitude of the electric field at the position of the charge.

Given: Magnitude of the charges, q = 1.0 × 10−6 C Electric force, F = 1.5 × 10−3 N We know that F = qE ⇒E=Fq=1.5×10-31.0×10-6 =1.5×103 N/C

The electric force experienced by a charge of 1.0 × 10⁻⁶ C is 1.5 × 10⁻³ N. Find the magnitude of the electric field at the position of the charge.

Given:
Magnitude of the charges, q = 1.0 × 10⁻⁶ C
Electric force, F = 1.5 × 10⁻³ N
We know that F = qE
$\Rightarrow E = \frac{F}{q} = \frac{1.5 \times 10^{- 3}}{1.0 \times 10^{- 6}} = 1.5 \times 10^{3} N / C$