The electric force experienced by a charge of 1-0 - 10-6 C is 1-5 - 10-3 N- N- Fin the magnitude of the electric field at the position of the charge-

F_e = θ E, E = F_e/θ = 1.5 × 10^ 3/1.0 × 10^ 6 = 1.5 × 10^3 N/C ...

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Standard XII

Physics

Electric Field

The electric ...

Question

The electric force experienced by a charge of $1.0 \times 10^{- 6} C$ is $1.5 \times 10^{- 3} N .$ N. Fin the magnitude of the electric field at the position of the charge.

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Solution

$F_{e} = θ E, E = \frac{F_{e}}{θ} = \frac{1.5 \times 10^{- 3}}{1.0 \times 10^{- 6}} = 1.5 \times 10^{3} N / C$

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The electric force experienced by a charge of 1.0×10−6C is 1.5×10−3N. N. Fin the magnitude of the electric field at the position of the charge.

Fe=θE,E=Feθ=1.5×10−31.0×10−6=1.5×103N/C

The electric force experienced by a charge of $1.0 \times 10^{- 6} C$ is $1.5 \times 10^{- 3} N .$ N. Fin the magnitude of the electric field at the position of the charge.

$F_{e} = θ E, E = \frac{F_{e}}{θ} = \frac{1.5 \times 10^{- 3}}{1.0 \times 10^{- 6}} = 1.5 \times 10^{3} N / C$