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Question

The electric force on a charge q1 due to q2 is (4^i3^j) N. The unit vector in the direction of electirc force on q2 due to q1 will be:

A
45^i35^j
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B
45^i+35^j
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C
45^i+35^j
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D
4^i+3^j
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Solution

The correct option is C 45^i+35^j
From Newton's third law,
the interaction force between charges is equal and opposite in nature.
F12=F21

F12=(4^i3^j) N

Thus, F21=F12

F21=(4^i+3^j) N

The unit vector in the direction of electric force on q2 is,
F21=F21|F21|

F21=4^i+3^j16+9

F21=45^i+35^j

Hence, option (b) is correct.

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