The electric intensity at a point near a charged conductor having a charge density $σ$ is :

\frac{σ}{{4 k E}_{0}}

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\frac{σ}{{2 k E}_{0}}

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\frac{2 σ}{{k E}_{0}}

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\frac{σ}{{k E}_{0}}

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Solution

The correct option is A $\frac{σ}{{4 k E}_{0}}$
The electric intensity at a point near a charged conductor having a charge density $= σ$
Using Gauss's law we say $φ = \frac{σ}{ϵ_{0}}$
Now this is the charge conductor then.
electric intensity $= \frac{σ}{4 k E_{0}}$

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The electric intensity at a point near a charged conductor having a charge density σ is :

The correct option is A σ4k E0The electric intensity at a point near a charged conductor having a charge density =σUsing Gauss's law we say φ=σϵ0Now this is the charge conductor then.electric intensity =σ4kE0

The electric intensity at a point near a charged conductor having a charge density $σ$ is :

The correct option is A $\frac{σ}{{4 k E}_{0}}$
The electric intensity at a point near a charged conductor having a charge density $= σ$
Using Gauss's law we say $φ = \frac{σ}{ϵ_{0}}$
Now this is the charge conductor then.
electric intensity $= \frac{σ}{4 k E_{0}}$