Question

the electric potential at a certain distance from a point charge is 600 V and the electric field at same point is 200N/C whatis potential at a distance of 9 m from same charge

Answer 1

Dear Student,
$$\begin{gathered} WeknowifchargeisQanddis\tan certhen \\ E=\frac{1}{4\pi {\epsilon }_0}\frac{Q}{r^2}------1 \\ V=\frac{1}{4\pi {\epsilon }_0}\frac{Q}{r}-----2 \\ orEr=V------3 \\ soaccordingtoquestionputvaluesofEandV \\ 200r=600 \\ r=3 \\ putin2 \\ Q=600\times 3\times 4\pi {\epsilon }_{0}C \\ sopotentialatr=9 \\ V=\frac{1}{4\pi {\epsilon }_0}\frac{Q}{r}=\frac{1}{4\pi {\epsilon }_0}\frac{600\times 3\times 4\pi {\epsilon }_0}{9}=200V \end{gathered}$$
Regard