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Byju's Answer
Standard XII
Physics
Superposition of Electric Fields
The electric ...
Question
The electric potential at a point
(
x
,
y
)
in an electric field is given by
V
=
6
x
y
+
y
2
−
x
2
Calculate the electric field at that point.
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Solution
→
E
=
−
→
∇
V
,
→
E
=
−
∂
V
∂
x
^
i
−
∂
V
∂
y
^
j
−
∂
V
∂
z
^
k
→
V
=
[
6
x
y
+
y
2
−
x
2
]
→
E
=
−
∂
∂
x
(
6
x
y
+
y
2
−
x
2
)
^
i
−
∂
∂
y
[
6
x
y
+
y
2
−
x
2
]
˙
j
−
∂
∂
z
[
6
x
y
+
y
2
−
x
2
]
^
k
→
E
=
−
[
6
y
−
2
x
]
^
i
−
[
6
x
+
2
y
]
^
j
−
0
→
E
=
(
2
x
−
6
y
)
^
i
−
(
6
x
+
2
y
)
^
j
v
o
l
t
/
m
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