Question

the electric potential difference between two parallel plates is 2000volts.if the plates are separated by 2mm,what is the magnitude of electrostatic force on a charge of 4*10^-6c located midway between the plates?

Answer 1

Dear Student,


$$\begin{gathered} valueofelectricfieldE=\frac{2000}{0.002}=2*{10}^{6}V/m \\ force=qE=4*{10}^{-6}*2*{10}^6=8N \\ Regards \end{gathered}$$