wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The electric potential due to a point charge decreases uniformly from 120 V to 80 V as one moves on the x axis from x=1 cm to x=+1 cm. The electric field at the origin.

A
must be equal to 20 V/cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
must be equal to 20 V/m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
may be greater than 20 V/cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
may be less than 20 V/cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C may be greater than 20 V/cm
Given,

Electric potential at x1=1 cm is V1=120 V

Electric potential at x2=+1 cm is V2=80 V

Since the potential is uniformly decreasing, we can write that,

Ex=(V2V1x2x1)

Ex=(801201(1))=+20 V/cm

Since, Ex is x component of electric field vector. The effect of y component and z component will also be at origin.

Thus, the electric field at origin may be greater than +20 V/cm

Hence, option (c) is the correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon