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Question

The electric potential due to a uniform disc of surface charge density 0.5C/m2 and radius 3 cm, at a point 4 cm from the centre on its perpendicular axis is

A
4ε0
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B
8ε0
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C
14ε0
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D
18ε0
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Solution

The correct option is C 14ε0
So the formula to find the potential at an axial point for a charged disk is,
V=2πσ[r2+R2r]4πε0
Where,σ is the charge density, R is the radius of the disk and r is the distance of the point from the center. If you don’t know where this formula came from, I encourage you to take a pen and a paper and derive it. It's very simple. Try it! Anyways, substituting in the values of corresponding variables we get,
V=2π×0.5[32+424]4πε0V=14ε0

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