CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The electric potential $$V$$ at any point $$\left( x,y,z \right) $$ in space is given by $$V=3{ x }^{ 2 }$$ where $$x, y, z$$ are all in metre. The electric field at the point $$\left( 1m,0,2m \right) $$ is


A
6Vm1 along negative x-axis
loader
B
6Vm1 along positive x-axis
loader
C
12Vm1 along negative x-axis
loader
D
12Vm1 along positive x-axis
loader
E
8Vm1 along negative x-axis
loader

Solution

The correct option is A $$6V{ m }^{ -1 }$$ along negative $$x$$-axis
Electric potential $$V=3{ x }^{ 2 }$$
$$E=-\dfrac { dV }{ dx } $$
$$E=-\dfrac { d }{ dx } \left( 3{ x }^{ 3 } \right) $$
$$E=-6x$$
At the point $$\left( 1,0,2 \right) $$
Electric field $$E=6\times 1=-6{ V }/{ m }$$
Thus electric field at $$(1m,0,2m)$$ is  $$6Vm^{-1}$$ along negative $$x-$$ axis.

Physics
NCERT
Standard XII

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
Same exercise questions
View More


similar_icon
People also searched for
View More



footer-image