CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The electric potential V (in volt ) varies with distance x (in meter) according to the relation V=5+4x2. The force experienced by a negative charge of 2 μC located at x=0.5 m is

A
4×106 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2×106 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8×106 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
6×108 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 8×106 N
Given, V=5+4x2

E=dVdx=ddx[5+4x2]

E=(0+8x)=8x

At x=0.5 m

|E|=|8×0.5|=4 NC1

Electric force
F=Eq=(4)(2×106)=8×106 N

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (c) is the correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Electric Field
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon