The electric potential V is given as a function of distance x (metre) by $V = (5 x^{2} - 10 x - 9)$ volt. Value of electric field at $x = 1$ m is:

20

V/m

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6

V/m

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11

V/m

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zero

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Solution

The correct option is A $20$ V/m

We know, $E = - \frac{d V}{d x}$

$V = 5 x^{2} - 10 x - 9$

$\frac{d V}{d x} = 10 x - 10$

so, $E = - (10 x - 10)$

For $x = 1 m$ , the value of $E = - (10 - 10) = 0 V / m$

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