Question

# The electric potential V is given as a function of distance x (metre) by $$V=(5x^2-10x-9)$$ volt. Value of electric field at $$x=1$$m is:

A
20 V/m
B
6 V/m
C
11 V/m
D
zero

Solution

## The correct option is A $$20$$ V/m We know, $$E=-\dfrac{dV}{dx}$$ $$V=5x^2 - 10x-9$$ $$\dfrac{dV}{dx}=10x-10$$ so, $$E=-(10x - 10)$$ For $$x=1 m$$, the value of $$E=-(10 - 10)= 0 V/m$$ PhysicsNCERTStandard XII

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