Question

The Electric potential vs position $(V-r)$ curve for the charged spherical shell of radius $R$ will be

• A.
  
• B.
• C.
  
• D.

Answer 1

The correct option is C



(i) Inside the spherical shell, the potential is constant. (straight line to r-axis)

$V=\frac{1}{4\pi {\epsilon }_0}\frac{q}{R}$


(ii) Outside the proportional to $r$

$V=\frac{1}{4\pi {\epsilon }_0}\frac{q}{r}$

i.e $V\propto \frac{1}{r}$.
Hence the curve is a rectangular hyperbola.

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (c) is the correct answer.