The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 600nm is incident on it. The energy band gap (in eV) for the semiconductor is
A
1.50
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B
.075
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C
2.06
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D
1.35
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E
0.90
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Solution
The correct option is B2.06 Given, λ=600nm=600×10−19m, We know that, energy gap =hcλ =6.62×10−34×3×108600×10−9×1.6×1019=2.06eV.