Question

The electrical conductivity of a semiconductor increases when radiation of the wavelength shorter than $2480nm$ is incident on it.The bandgap (in eV) for the semiconductor is

• A. $0.5$
• B. $0.9$
• C. $0.7$
• D. $1.1$

Answer 1

The correct option is A $0.5$

We know that $E=\frac{hc}{\lambda }$

$\Rightarrow E=\frac{6.6\times {10}^{-34}\times 3\times {10}^8}{2480\times {10}^{-9}}=0.5ev$

Therefore the band gap for the semiconductor is $0.5ev$

So the correct option is $A$