The electrical resistance in ohms of a certain thermometer varies with temperature according to the approximate law R=R0 [1 +a(T-T0)]The resistance is 101.6at the triple point of water 273.16K and 165.5at the normal melting point of lead (600.5K).What is the temperature when the resistance is 123.4?

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Q. The electrical resistance of pure platinum increases linearly with increasing temperature over a small range of temperature. This property is used in a Platinum resistance thermometer. The relation between

R_{θ}

(Resistance at

θ K

) and

R_{0}

(Resistance at

θ_{0} K)

is given by

R_{θ} = R_{0} [1 + α (θ - θ_{0})]

, where

α =

temperature coefficient of resistance. Now, if a Platinum resistance thermometer reads

0^{\circ} C

when its resistance is

80 Ω

and

100^{\circ} C

when its resistance is

90 Ω

, find the temperature at which its resistance is

86 Ω

A resistance thermometer reads R = 20.0 $Ω$ , 27.5 $Ω$ , and 50.0 $Ω$ at the ice point ( $0^{\circ} C$ ), the steam point ( $100^{\circ} C$ ) and the zinc point ( $420^{\circ} C$ ) respectively. Assuming that the resistance varies with temperature as $R_{θ} = R_{0} (1 + α θ + β θ^{2})$ , find the values of $R_{0}, α$ and $β$ . Here $θ$ represents the temperature on Celsius scale.