Question

The electrochemical equivalent of silver is $0.0011180g$. When an electric current of $0.5$ ampere is passed through an aqueous silver nitrate solution for $200sec$, the amount of silver deposited is:

• A. $1.1180g$
• B. $0.11180g$
• C. $5.590g$
• D. $0.5590g$

Answer 1

Answer: (B)

$0.11180g$

According to the data given when $1$ e is passed the amount of silver,

deposited is $0.0011180g$

$\therefore (0.5\times 200)c$ is passed

then $(0.0011180\times 100)g$

of silver gets deposited

$=0.11180g$