The electrode potential becomes equal to standard electrode potential when reactants and products concentration ratio is :-

equal to 1

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greater than 1

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less than 1

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none of the above

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Solution

The correct option is A equal to 1
As we know,
$E = {E^{0}}_{c e l l} - \frac{0.0591}{n} log [\frac{P}{R}]; 1 = [\frac{P}{R}]$
$E = {E^{0}}_{c e l l}$

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The electrode potential becomes equal to standard electrode potential when reactants and products concentration ratio is :-

The correct option is A equal to 1As we know,E=E0cell−0.0591nlog[PR];1=[PR]E=E0cell

The correct option is A equal to 1
As we know,
$E = {E^{0}}_{c e l l} - \frac{0.0591}{n} log [\frac{P}{R}]; 1 = [\frac{P}{R}]$
$E = {E^{0}}_{c e l l}$