The electrode potentials for Cu2- aq - e- - Cu-aq and Cu- aq - e- - Cu s are -0-15 V and -0-50 V respectively- They value of E0Cu2-Cu

Cu^2+ (aq) + e^ → Cu^+(aq) Δ G^∘_1=+0.15 V Cu^+ (aq) + e^ → Cu (s) Δ G^∘_2=+0.50 V Cu^2+ (aq) + 2e^ → Cu(s) Δ G^∘_3=? Δ G^∘_3 = Δ G^∘_1+ Δ G^∘_2 ⇒ 2FE^∘ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Accountancy

Current Ratio

The electrode...

Question

The electrode potentials for $C u^{2 +} (a q) + e^{-} \to C u^{+} (a q) a n d C u^{+} (a q) + e^{-} \to C u (s) a r e + 0.15 V a n d + 0.50 V$ respectively. They value of $E_{C u^{2 +} / C u}^{0}$

0.650 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.500 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.150 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.325 V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $0.325 V$
$C u^{2 +} (a q) + e^{-} \to C u^{+} (a q) Δ G_{1}^{\circ} = + 0.15 V C u^{+} (a q) + e^{-} \to C u (s) Δ G_{2}^{\circ} = + 0.50 V$
$C u^{2 +} (a q) + 2 e^{-} \to C u (s) Δ G_{3}^{\circ} = ?$
$Δ G_{3}^{\circ} = Δ G_{1}^{\circ} + Δ G_{2}^{\circ}$
$\Rightarrow - 2 F E^{\circ} = - 1 F \times 0.15 + (- 1 F \times 0.50)$
$\Rightarrow - 2 F E^{\circ} = - 0.65 F$
$∴ E^{\circ} = \frac{0.65}{2} = 0.325 V$

Suggest Corrections

Similar questions

Q. The electrode potentials for:

C u^{2 +} (a q) + e^{-} \to C u^{+} (a q)

C u^{+} (a q) + e^{-} \to C u (s)

are + 0.15 V and 0.50 V respectively. The value of

E^{0} c u^{2} / C u

will be :

Q. The electrode potentials for

C u_{(a q)}^{2 +} + e^{-} \to C u_{(a q)}^{+}

and

C u_{(a q)}^{+} + e^{-} \to C u_{(s)}

Are

+ 0.15 V

and

+ 0.50 V

respectively.
The value of

E_{C u^{2 +} / C u}^{\circ}

will be

Q. The electrode potential for

C u_{(a q)}^{2 +} + e^{-} \to C u_{(a q)}^{+}

and

C u_{(a q)}^{+} + e^{-} \to C u_{(s)}

are +0.15 V and +0.50 V respectively. The value of

E_{C u^{2 +} / C u}^{o}

will be:

Q. The electrode potential for

C u_{(a q)}^{2 +} + e^{-} \to C u_{(a q)}^{+}

and

C u_{(a q)}^{+} + e^{-} \to C u_{(s)}

are +0.15 V and +0.50 V respectively. The value of

E_{C u^{2 +} / C u}^{o}

will be:

Q. Consider the following half cells

C u_{(s)} \to C u_{(a q)}^{2 +} + 2 e^{-}; E^{o} = - 0.325 V

C u_{(a q)}^{+} + e^{-} \to C u_{(s)}; E^{o} = 0.50 V

The

E^{o}

for the reaction

2 C u_{(a q)}^{+} \to C u_{(a q)}^{2 +} + C u_{(s)}

Join BYJU'S Learning Program

The electrode potentials for Cu2+(aq)+e−→Cu+(aq) and Cu+ (aq)+e−→Cu (s) are +0.15 V and +0.50 V respectively. They value of E0Cu2+/Cu

The correct option is D 0.325 VCu2+(aq)+e−→Cu+(aq) ΔG∘1=+0.15 VCu+ (aq)+e−→Cu (s) ΔG∘2=+0.50 V Cu2+(aq)+2e−→Cu(s) ΔG∘3=? ΔG∘3=ΔG∘1+ΔG∘2 ⇒−2FE∘=−1F×0.15+(−1F×0.50) ⇒−2FE∘=−0.65F ∴ E∘=0.652=0.325V

The electrode potentials for $C u^{2 +} (a q) + e^{-} \to C u^{+} (a q) a n d C u^{+} (a q) + e^{-} \to C u (s) a r e + 0.15 V a n d + 0.50 V$ respectively. They value of $E_{C u^{2 +} / C u}^{0}$