The electrode potentials for - Cu2-aq-e- - Cu- aq and Cu- aq - e- - Cus are -0-15V and -0-50V respectively- The value of E-Cu2-Cu will be-

The $E^{\circ}$ for $C u^{2 +} / C u^{+}$ ; $C u^{+} / C u$ , $C u^{2 +} / C u$ are 0.15V, 0.50 V and 0.325 V respectively. The redox cell showing redox reaction $2 C u^{+} \to C u^{2 +} + C u$ is made. The $E^{\circ}$ of this cell reaction and $Δ G^{\circ}$ may be:

Q. The electrode potential for

C u_{(a q)}^{2 +} + e^{-} \to C u_{(a q)}^{+}

and

C u_{(a q)}^{+} + e^{-} \to C u_{(s)}

are +0.15 V and +0.50 V respectively. The value of

E_{C u^{2 +} / C u}^{o}

will be:

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The electrode potentials for : Cu2+(aq)+e−→Cu+(aq) and Cu+(aq)+e−→Cu(s) are +0.15V and +0.50V respectively. The value of E∘Cu2+/Cu will be:

The correct option is C 0.325VCu2++1e−→Cu+ ; E01=0.15V,ΔG01=−n1E01FCu++1e−→Cu ; E02=0.50V,ΔG02=−n2E02FCu2++2e−→Cu ; ΔG∘=ΔG∘1+ΔG∘2i.e.(−2)nE∘F=(−1)n1E∘1F+(−1)n2E∘2FE∘=n1ΔE∘1+n2ΔE∘2n=0.15×1+0.50×12=0.325V

The electrode potentials for : $C u^{2 +} (a q) + e^{-} \to C u^{+} (a q)$ and $C u^{+} (a q) + e^{-} \to C u (s)$ are +0.15V and +0.50V respectively. The value of $E_{C u^{2 +} / C u}^{\circ}$ will be: