The electrode potentials for Cu2-aq-e- Cu-aq and Cu2-aq-e- Cu s are-0-15 V and-0-50 V respectively- The value of E0Cu2-Cu will be-

Cu^2+(aq) + e^ → Cu^+(aq) nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp;(i) Cu^+(aq) + e^ → Cu(s) nbsp; nbsp; nbsp; nbsp; nbsp; ...

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Gibb's Energy and Nernst Equation

The electrode...

Question

The electrode potentials for $C u^{2 +} (a q) + e^{-} \to C u^{+} (a q) and C u^{2 +} (a q) + e^{-} \to C u (s) are + 0.15 V and + 0.50 V$ respectively. The value of $E_{C u^{2 +} / C u}^{0}$ will be:

0.150 V

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0.500 V

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0.325 V

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0.650 V

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Solution

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Similar questions

C u_{(a q)}^{2 +} + e^{-} \to C u_{(a q)}^{+}

C u_{(a q)}^{+} + e^{-} \to C u_{(s)}

+ 0.15 V

+ 0.50 V

E_{C u^{2 +} / C u}^{\circ}

C u_{(a q)}^{2 +} + e^{-} \to C u_{(a q)}^{+}

C u_{(a q)}^{+} + e^{-} \to C u_{(s)}

E_{C u^{2 +} / C u}^{o}

C u_{(a q)}^{2 +} + e^{-} \to C u_{(a q)}^{+}

C u_{(a q)}^{+} + e^{-} \to C u_{(s)}

E_{C u^{2 +} / C u}^{o}

E^{\circ}

C u_{(s)} + Z n_{(a q)}^{2 +} \to Z n_{(s)} + C u_{(a q)}^{2 +}

E_{C u^{2 +} / C u}^{0} = 0.34 V, E_{Z n^{2 +} / Z n}^{0} = - 0.76 V

E_{C e l l}^{o}

Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)

E_{C u^{2 +} / C u}^{\circ} = 0.34 V, E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 V

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