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Valency and Oxidation States

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Question

The electron affinity of 4th-period elements is less than that of 3rd-period elements.

A

True

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B

False

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Solution

The correct option is A True
Electron affinity of 4 period is less than that of 3 period, because of more number of shells on 4 period.

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Q. Assertion :Electron affinity of 4th period elements is less than that of 3rd period elements. Reason: Fourth period elements are larger than that of third period. Hence, accepting tendency of electrons will be less for fourth period because of large size that is because of addition of new shell.

Q. Assertion :Manganese has a less favourable electron affinity than its neighbours in either side. Reason: The magnitude of an elements electron affinity depends on the elements valence shell electronic configuration.

Q. Number of correct statement among the following is
(A) The electron affinity of

S i

is greater than that of

C

B e O

is amphoteric while

B_{2} O_{3}

is acidic.
(C) The ionization energy of

G a

is less than that of

A l

.
(D) The ionization energy of elements of

C u

- group is less than that of the respective elements of

Z n

Q. A, B, C are three elements in which B is an inert gas other than helium. With this information complete the following table.

Element	Atomic number	No. of electrons in the valence shell	Group to which the element belongs
A B C	Z − 1 Z Z + 1	.... .... ....	.... .... ....

Also, explain the following:
(i) Electron affinity of element A is more than that of element C.
(ii) Ionization energy of element C is less than that of element A.
(iii) Electron affinity of B is zero.

Q. In which of the following , the electron affinity of the second element is more than that of the first element is :

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