Question

The electron beam in a colour TV is accelerated through 32 kV and then strikes the screen. What is the wavelength of the most energetic X-ray photon ?

Answer 1

Given V = 32 KV = 32 $\times {10}^3$ V

When accelerated through 32 KV

E =32 $\times {10}^3$ eV

$\lambda =\frac{hc}{E}=\frac{1242}{32\times {10}^3}$

= 38.8 $\times {10}^{-3}$ nnm

= 38.8 pm