Question

The electron belongs to the angular momentum of an $e^{-}$in a Bohr's orbit of H atom is $4.2178\times {10}^{-34}Kg.m^2.Se{c}^{-1}$.

• A. K - shell
• B. L - shell
• C. N - shell
• D. M - shell

Answer 1

The correct option is C

N - shell

$\frac{nh}{2\pi }$=$4.2178\times {10}^{-34}$

$n$ = $\frac{2\pi \times 4.2178\times {10}^{-34}}{h}$

=$\frac{2\times 3.14\times 4.2178\times {10}^{-34}}{6.625\times 10-34}$

$n$ = $4$

N-shell