The electron configuration for calcium ion :

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}

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1 s^{2} 2 s^{2} p^{6} 3 s^{2} 3 p^{6} 4 s^{2}

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1 s^{2} 2 s^{2} p^{6} 3 s^{2} 3 p^{6} 4 s^{1}

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1 s^{2}

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1 s^{2} 2 s^{2} 2 p^{6} 3 p^{1}

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Solution

The correct option is A $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}$
The electron configuration for calcium atom (Z = 20 ) is
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2}$
Ca atom loses two electrons to form $C a^{2 +}$ ion
The electron configuration for calcium ion is
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}$

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Similar questions

The electronic configuration of Ti is 1 $s^{2}$ 2 $s^{2}$ 2 $p^{6}$ 3 $s^{2}$ 3 $p^{6}$ 3 $d^{2}$ 4 $s^{2}$ and it represents

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {3 d}^{6} {4 s}^{1}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {4 s}^{2}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{1}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{5}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {4 s}^{1}

{(I E)}_{1}

{(I E)}_{4}

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