The electron configuration of an element M is [Ar] $3 d^{10} 4 s^{2} 4 p^{3}$ . Then M belongs to :

V B

group

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V I I I

group

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V A

group

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0

group

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Solution

The correct option is A $V A$ group
The electron configuration of an element M is $[A r] 3 d^{10} 4 s^{2} 4 p^{3}$ . In the given configuration, the outer electronic configuration of the element M is $4 s^{2} 4 p^{3}$ which is in the form of $n s^{2} n p^{3}$ which is the general outer electronic configuration of VA group (group 15). So, the element M belongs to VA group.

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n s^{2} n p^{5}

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