Question

The electronic distribution in an aluminum atom is

• A. $2,8,3$
• B. $2,8,2$
• C. $8,2,3$
• D. $2,3,8$

Answer 1

The correct option is A

$2,8,3$

The correct option is option A

The explanation for the correct option:

1. Aluminum is an element with the symbol $\mathrm{Al}$ and atomic number $13$.
2. Its electronic configuration is according to the Aufbau principle i.e. it explains that in an atom's or ion's ground state, electrons first occupy subshells with the lowest possible energy before moving on to subshells with higher energy.
3. Electronic configuration will follow the pattern$1\mathrm{s},2\mathrm{s},2\mathrm{p},3\mathrm{s},3\mathrm{p},4\mathrm{s},3\mathrm{d},4\mathrm{p},5\mathrm{s}$ and so on with s orbital having two electrons, p orbital having six electrons, and d-orbital having ten electrons.
4. Electronic configuration of Aluminum is $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^1$
5. Therefore, in the first energy there are two electrons followed by the second energy level having eight electrons, and the third energy having three electrons.

Final answer: The electronic distribution in an aluminum atom is $2,8,3$