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Question

The electron identified by quantum number n and l

1.n=4,l=1 2.n=4,l=0

3.n=3,l=2 4.n=3,l=1

Can be placed in the order of increasing energy from the lowest to highest as

A) 4<2<3<1 B) 2<4<1<3

C) 1<3<2<4. D) 3<1<4<2

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Solution


(1) n = 4, l = 1 ⇒ 4p orbital
(2) n = 4, l = 0 ⇒ 4s orbital
(3) n = 3, l = 2 ⇒ 3d orbital
(4) n = 3, l = 1 ⇒ 3p orbital

According to aufbau principle, energies of above mentioned orbitals are in the order of
(4) 3p < (2) 4s < (3) 3d < (1) 4p

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