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Standard XII

Physics

Characteristics of Bohr's Atomic Model

The electron ...

Question

The electron in a hydrogen atom makes a transition from $n = n_{1}$ to $n = n_{2}$ state. The time period of the electron in the initial state is eight times that in the final state. The possible values of $n_{1}$ and $n_{2}$ are

n_{1} = 4, n_{2} = 2

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n_{1} = 8, n_{2} = 2

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n_{1} = 8, n_{2} = 3

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n_{1} = 6, n_{2} = 2

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Solution

The correct option is A $n_{1} = 4, n_{2} = 2$
Given: $T_{n_{1}} = 8 T_{n_{2}}$
$\Rightarrow n_{1} = 2 n_{2}$
Hence, the answer is A.

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The electron in a hydrogen atom makes a transition from n=n1 to n=n2 state. The time period of the electron in the initial state is eight times that in the final state. The possible values of n1 and n2 are

The correct option is A n1=4,n2=2Given: Tn1=8Tn2⇒n1=2n2Hence, the answer is A.

The electron in a hydrogen atom makes a transition from $n = n_{1}$ to $n = n_{2}$ state. The time period of the electron in the initial state is eight times that in the final state. The possible values of $n_{1}$ and $n_{2}$ are

The correct option is A $n_{1} = 4, n_{2} = 2$
Given: $T_{n_{1}} = 8 T_{n_{2}}$
$\Rightarrow n_{1} = 2 n_{2}$
Hence, the answer is A.