The electron in a hydrogen atom makes transition from M shell to L shell. The ratio of magnitudes of initial to final centripetal acceleration of the electron is

9 : 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

81 : 16

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 : 9

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 : 81

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $16 : 81$
Centripetal acceleration of electron is $a = \frac{v^{2}}{R}$
We know that $v \propto \frac{z^{2}}{n^{2}}, R \propto \frac{n^{2}}{z}$
Hence,
$a \propto \frac{z^{2} / n^{2} . z}{n^{2}} \propto \frac{z^{3}}{n^{4}} \propto \frac{1}{n^{4}}$

As transition takes place from M shell to L shell, $n$ changes from $3$ to $2$ , hence we get

$∴ a_{M} : a_{L} = 16 : 81$

Suggest Corrections

Similar questions

Q. The electron in a hydrogen atom makes transition from M shell to L. The ratio of magnitudes of initial to final centripetal acceleration of the electron is

Q. Determine the wavelength emitted for an electronic transition from M shell

(n = 3)

to K shell

(n = 1)

in a hydrogen atom.

(R = 109, 677 c m^{- 1})

Q. An electron in a hydrogen atom makes a transition from

n = n_{1}

n = n_{2}

. The time period of the electron in the initial state is eight times that in the final state. The possible values of

n_{1}

and

n_{2}

are

The electron in hydrogen atom makes a transition from $n = n_{1} to n = n_{2}$ state. The time period of the electron in the initial state is eight times that in the final state. The possible values are

Q. An electron in a hydrogen atom makes a transition

n_{1} \to n_{2}

where

n_{1}

and

n_{2}

are principal quantum numbers of the states. Assume the Bhor's model to be valid. The time period of the electron in the initial states is eight times to that of final state. What is ratio of

\frac{n_{1}}{n_{2}}

Join BYJU'S Learning Program

The electron in a hydrogen atom makes transition from M shell to L shell. The ratio of magnitudes of initial to final centripetal acceleration of the electron is

The correct option is D 16:81Centripetal acceleration of electron is a=v2R We know that v∝z2n2,R∝n2z Hence, a∝z2/n2.zn2∝z3n4∝1n4 As transition takes place from M shell to L shell, n changes from 3 to 2, hence we get ∴aM:aL=16:81