You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Moseley's Law

The electron ...

Question

The electron in hydrogen atom makes a transition from $n = n_{1} to n = n_{2}$ state. The time period of the electron in the initial state is eight times that in the final state. The possible values are

$n_{1} = 4, n_{2} = 2$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$n_{1} = 8, n_{2} = 2$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$n_{1} = 8, n_{1} = 2$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$n_{1} = 6, n_{2} = 2$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$n_{1} = 4, n_{2} = 2$

$T = \frac{2 π r}{v} and r \propto n^{2}, v \propto 1 / n \Rightarrow T \propto n^{3} \frac{T_{1}}{T_{2}} = {(\frac{n_{1}}{n_{2}})}^{3} 8 = {(\frac{n_{1}}{n_{2}})}^{3} o r \frac{n_{1}}{n_{2}} = 2$

Suggest Corrections

Similar questions

The electron in hydrogen atom makes a transition from $n = n_{1} to n = n_{2}$ state. The time period of the electron in the initial state is eight times that in the final state. The possible values are

Q. An electron in a hydrogen atom makes a transition from

n = n_{1}

and

n = n_{2}

The time period of the electron in the initial state is eight times that in the final state. The possible values of

n_{1} and n_{2}

are

Q. The electron in a hydrogen atom makes a transition form

n = n_{1}

n = n_{2}

state. The time period of the electron in the initial state

(n_{1})

is eight times that in the final state

(n_{2})

. The possible values of

n_{1}

and

n_{2}

are.

Q. The electron in hydrogen atom makes a transition

n_{1} \to n_{2}

where

n_{1} and n_{2}

are principle quantum numbers of the two states. The time period of the electron in the initial state is eight times that of in the final state. The possible values of

n_{1} and n_{2}

are,

Join BYJU'S Learning Program

The electron in hydrogen atom makes a transition from n=n1 to n=n2 state. The time period of the electron in the initial state is eight times that in the final state. The possible values are

The correct option is A n1=4,n2=2 T=2πrv and r∝n2,v∝1/n⇒T∝n3T1T2=(n1n2)38=(n1n2)3 or n1n2=2

The electron in hydrogen atom makes a transition from $n = n_{1} to n = n_{2}$ state. The time period of the electron in the initial state is eight times that in the final state. The possible values are

The correct option is A
$n_{1} = 4, n_{2} = 2$

$T = \frac{2 π r}{v} and r \propto n^{2}, v \propto 1 / n \Rightarrow T \propto n^{3} \frac{T_{1}}{T_{2}} = {(\frac{n_{1}}{n_{2}})}^{3} 8 = {(\frac{n_{1}}{n_{2}})}^{3} o r \frac{n_{1}}{n_{2}} = 2$