Question

The electron in the ground state of the hydrogen atom absorbs 12.1 eV of energy. It will jump to the orbit

• A. $2^{nd}$
• B. $3^{rd}$
• C. $4^{th}$
• D. $5^{th}$

Answer 1

The correct option is B $3^{rd}$

Energy in the gound state $(n=1)=-\frac{13.6}{n^2}eV$

=$-13.6eV$

After absorbing 12.1 ev now energy = $-13.6+12.1$

= $-1.5eV$

$\therefore \frac{-13.6}{n^2}=-1.5$ or $n^2=9$ (or) $n=3$