Question

The electron is present in an orbit of energy state $-1.51$ eV, then angular momentum of the electron is

• A. $2h/\pi$
• B. $h/\pi$
• C. $3h/2\pi$
• D. $7h/\pi$

Answer 1

Answer: (C)

$3h/2\pi$

Given : $E_n=-1.51$ eV

Using $E_n=\frac{-13.6}{n^2}$ eV (for H-atom)

$\therefore$ $-1.51=\frac{-13.6}{n^2}$ $⟹n=3$

Thus angular momentum $L=\frac{nh}{2\pi }=\frac{3h}{2\pi }$