The electronegativity of the following elements increase in order:

C, N, Si, P

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N, Si, C, P

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Si, P, C, N

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P, Si, N, C

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Solution

The correct option is C
Si, P, C, N

Si and P are in third period while C and N are in $2^{N D}$ period. Second period have higher electronegativity than third period N is smaller in size than C, so N is more electronegativity than C. Similarly electronegativity of P is higher than Si.

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The electronegativity of the following elements increase in order:

The correct option is C Si, P, C, N Si and P are in third period while C and N are in 2ND period. Second period have higher electronegativity than third period N is smaller in size than C, so N is more electronegativity than C. Similarly electronegativity of P is higher than Si.

The correct option is C
Si, P, C, N

Si and P are in third period while C and N are in $2^{N D}$ period. Second period have higher electronegativity than third period N is smaller in size than C, so N is more electronegativity than C. Similarly electronegativity of P is higher than Si.