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Byju's Answer

Standard XII

Chemistry

Periodicity

The electroni...

Question

The electronic arrangements of four elements i, ii, iii, iv are:
(i) $1 s^{2}$ (ii) $1 s^{2} 2 s^{2} 2 p^{2}$ (iii) $1 s^{2} 2 s^{2} 2 p^{5}$ (iv) $1 s^{2} 2 s^{2} 2 p^{6}$
The tendency to form ionic bond is maximum in:

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iii

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Solution

The correct option is C iii
$1 s^{2} 2 s^{2} 2 p^{5}$ having tendency to accept electron and fulfill its shell. Hence have maximum tendency to form ionic compound.

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Similar questions

Q. The electronic structure of four element a, b, c and d are
(i)

1 s^{2}

(ii)

1 s^{2}, 2 s^{2}

(iii)

1 s^{2}, 2 s^{2} 2 p^{5}

(iv)

1 s^{2}, 2 s^{2} 2 p^{6}

The tendency to form bond is greatest in:

Arrange the elements with the following electronic configurations in the increasing order of electron affinity

(i) $1 s^{2} 2 s^{2} 2 p^{3}$ (ii) $1 s^{2} 2 s^{2} 2 p^{4}$ (iii) $1 s^{2} 2 s^{2} 2 p^{5}$ (iv) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4}$

Q. The electronic configuration of few elements is given below. Mark the statement which is not correct about these elements.
(i)

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

(ii)

1 s^{2} 2 s^{2} 2 p^{5}

(iii)

1 s^{2} 2 s^{2} 2 p^{6}

(iv)

1 s^{2} 2 s^{2} 2 p^{3}

Q. Arrange the following compounds in the order of decreasing tendency towards

S N_{2}

reaction.

C H_{3} C H_{2} C H_{2} C l . . . . . . . . . (i)

C H_{3} C H_{2} C H C l C H_{3} . . . . . . . (i i)

(C H_{3})_{2} C H C H_{2} C l . . . . . . . . (i i i)

(C H_{3})_{3} C - C l . . . . . . . . . . (i v)

Arrange the following: $C H_{3} C H_{2} C H_{2} C l (I), C H_{3} C H_{2} C H C l C H_{3} (I I) {(C H_{3})}_{2} C H C H_{2} C l (I I I) a n d {(C H_{3})}_{3} C - C l (I V)$ in order of decreasing tendency towards $S N^{2}$ reaction

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The electronic arrangements of four elements i, ii, iii, iv are:(i) 1s2 (ii) 1s22s22p2 (iii) 1s22s22p5 (iv) 1s22s22p6The tendency to form ionic bond is maximum in:

The correct option is C iii1s22s22p5 having tendency to accept electron and fulfill its shell. Hence have maximum tendency to form ionic compound.

The electronic arrangements of four elements i, ii, iii, iv are:
(i) $1 s^{2}$ (ii) $1 s^{2} 2 s^{2} 2 p^{2}$ (iii) $1 s^{2} 2 s^{2} 2 p^{5}$ (iv) $1 s^{2} 2 s^{2} 2 p^{6}$
The tendency to form ionic bond is maximum in:

The correct option is C iii
$1 s^{2} 2 s^{2} 2 p^{5}$ having tendency to accept electron and fulfill its shell. Hence have maximum tendency to form ionic compound.