Question

The electronic configuration of a di-positive ion M${}^{2+}$ is 2, 8, 14 and its mass number is 56. The number of protons present is :

Answer 1

Electronic configuration of M${}^{2+}$

= 2 + 8 + 14 = 24$e^{-}$

Since two e${}^{-}$ has been lost in forming M${}^{2+}$ ion from metal

so total number of electron in the neutral atom should be = $24+2=26$

The number of proton and electron are equal in a neutral atom.

Therefore number of proton is equal to 26.