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Question
The electronic configuration of a dispositive metal M2+ is, 2, 8, 14 and its atomic weight is 56 a.m.u. The number of neutrons in its nuclei would be
The electronic configuration of a dispositive metal M2+ is, 2, 8, 14 and its atomic weight is 56 a.m.u. The number of neutrons in its nuclei would be
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Solution
The correct option is A 30
Metals is 56M2+ (2 , 8 ,14) then n = A - Z
= 56 - 26 = 30
30
Metals is 56M2+ (2 , 8 ,14) then n = A - Z
= 56 - 26 = 30
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