Question

The electronic configuration of a metal $M$ is $1s^2,2s^2,2p^6,3s^1$. The formula of its oxides will be :

• A. $MO$
• B. $M_{2}O$
• C. $M_2{O}_3$
• D. $M{O}_2$

Answer 1

The correct option is B $M_{2}O$

Since it has 1 electron in its valence shell, hence it will lose 1 electron to attain octet and will become $M^{+}$ and will react with $O^{2-}$ to form $M_{2}O$.

Hence, option B is correct.