The electronic configuration of actinides is:

[R n] 5 f^{0 - 14} 6 d^{0 - 2} 7 s^{1}

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[R n] 5 f^{0 - 14} 6 d^{0} 7 s^{0}

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[R n] 5 f^{0 - 14} 6 d^{0 - 2} 7 s^{2}

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[R n] 5 f^{0 - 14} 6 d^{0 - 2} 7 s^{0}

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Solution

The correct option is C $[R n] 5 f^{0 - 14} 6 d^{0 - 2} 7 s^{2}$
General electronic configuration of actinides $= [R n] 5 f^{0 - 14} 6 d^{0 - 2} 7 s^{2}$
Hence, the correct option is C.

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The electronic configuration of U³⁺ ion is:

The element Z = 114 has been discovered recently. It will belong to which of the following family/group and electronic configuration? [NEET 2017]

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Protactinium or Pa (Z = 91) =[Rn]5f26d17s2

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