Question

The electronic configuration of an element is $1s^2,2s^2,2p^6,3s^2,3p^6,3d^5,4s^1$. This represents its

• A. Excited state
• B. Ground state
• C. Cationic form
• D. Anionic form

Answer 1

The correct option is B Ground state

$3d^{5}4s^1$ system is more stable than $3d^{4}4s^2$ system because of the half filled $d$-orbital. Hence former is the ground state configuration.