The electronic configuration of an element is 1s2,2s2,2p6,3s2,3p6,3d3,4s1. This represents its
A
Excited state
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B
Ground state
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C
Cationic form
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D
Anionic form
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Solution
The correct option is D Cationic form Electronic configuration belongs to d-block.
Here d block is neither half-filled nor fulfilled so s orbital of an element must have 2 electrons, but here in s orbital, only one electron is present. It means the element is in a cationic form with oxidation no +1.