The electronic configuration of an element is 1 s2 2 s2 2 p6 3 s2 3 p6 3 d5 4 s1- This represents its-A- Excited stateB- Ground stateC- Cationic formD- Anionic form

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Nomenclature of Coordination Compounds

The electroni...

Question

The electronic configuration of an element is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}$ . This represents its:

Excited state

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Ground state

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Cationic form

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Anionic form

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Solution

The correct option is B Ground state
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}$ is the ground state electronic configuration of $C r$ .

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Question 02

Which of the following options does not represent ground state electronic configuration of an atom ?

(a) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{8} 4 s^{2}$ (b) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{9} 4 s^{2}$ (c) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{1}$ (d) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}$

$X e F_{4}$ is formed by Xe in its

Q. If the electronic configuration of an element is

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}

then the number electrons involved in bonding will be:

Q. The electronic configuration of an element is

1 s^{2} 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{5}, 4 s^{1}

. This represents:

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The electronic configuration of an element is 1s22s22p63s23p63d54s1. This represents its:

The correct option is B Ground state1s22s22p63s23p63d54s1 is the ground state electronic configuration of Cr.

The electronic configuration of an element is $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}$ . This represents its:

The correct option is B Ground state
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}$ is the ground state electronic configuration of $C r$ .