The electronic configuration of an element with atomic number 29 is :

1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{6}, 3 d^{9}, 4 s^{2}

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1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{6}, 3 d^{10}, 4 s^{1}

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1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{6}, 3 d^{8}, 4 s^{2}, 4 p^{1}

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1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{6}, 3 d^{7}, 4 s^{2}, 4 p^{2}

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Solution

The correct option is B $1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{6}, 3 d^{10}, 4 s^{1}$
The electronic configuration of an element with atomic number 29 is
$1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{6}, 3 d^{10}, 4 s^{1}$

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Similar questions

1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{6}, 3 d^{10}, 4 s^{1}

An atom of an element contains 29 electrons and 35 neutrons. Deduce
(i) the number of protons

(ii) the electronic configuration of the element.

12

1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{6}, 3 d^{10}, 4 s^{1}

1 s^{2}, 2 s^{2}, 2 p^{5}

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