The electronic configuration of carbon is $1 s^{2} 2 s^{2} 2 p^{2}$ . There are 12 electrons in $C_{2}$ . The correct electronic configuration of $C_{2}$ molecule is:

(σ 1 s^{2}) (σ^{*} 1 s^{2}) (σ 2 s^{2}) (σ^{*} 2 s^{2}) (σ 2 p_{z}^{2}) (π 2 p_{x}^{2})

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(σ 1 s^{2}) (σ^{*} 1 s^{2}) (σ 2 s^{2}) (σ^{*} 2 s^{2}) (π 2 p_{x}^{2} = π 2 p_{y}^{2})

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(σ 1 s^{2}) (σ^{*} 1 s^{2}) (σ 2 s^{2}) (σ^{*} 2 s^{2}) (σ 2 p_{z}^{2}) (π 2 p_{x}^{1} = π 2 p_{y}^{1})

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(σ 1 s^{2}) (σ^{*} 1 s^{2}) (σ 2 s^{2}) (σ^{*} 2 s^{2}) (π 2 p_{x}^{2} = π 2 p_{y}^{1})

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Solution

The correct option is B $(σ 1 s^{2}) (σ^{} 1 s^{2}) (σ 2 s^{2}) (σ^{} 2 s^{2}) (π 2 p_{x}^{2} = π 2 p_{y}^{2})$
Because $C_{2}$ is diamagnetic compound and
$C_{2} (12 e^{-}) = σ 1 s^{2} σ^{} 1 s^{2} σ 2 s^{2} σ^{} 2 s^{2} π 2 p x^{2} = π 2 p^{2} y$
It does not contain any unpaired electrons.

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Which of the following represent the correct electronic configuration of $O_{2}$ ?

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σ 1 s^{2} σ^{+} 1 s^{2} σ 2 s^{2} σ^{+} 2 s^{2} σ^{+} 2 s^{2} σ 2 p_{x}^{2}

{\begin{matrix} π 2 p_{y}^{2} π 2 p_{z}^{2} \end{matrix}

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