The electronic configuration of ${C r}^{3 +}$ is:

[A r] {3 d}^{4} {4 s}^{2}

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[A r] {3 d}^{3} {4 s}^{0}

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[A r] {3 d}^{2} {4 s}^{1}

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[A r] {3 d}^{5} {4 s}^{1}

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Solution

The correct option is B $[A r] {3 d}^{3} {4 s}^{0}$

The electronic configuration of $C r (24)$ atom is:
$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1} 3 d^{5}$ which is half-filled d-orbital.
$C r^{3 +}$ has 3 electrons removed from the outermost shell.

Therefore, the electronic configuration comes out to be $[A r] 3 d^{3}$ .

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4 s^{1}

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{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {3 d}^{6} {4 s}^{1}

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