The electronic configuration of ${C u}^{2 +}$ ion is :

[A r] {3 d}^{8} {4 s}^{1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[A r] {3 d}^{9} {4 s}^{0}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[A r] {3 d}^{7} {4 s}^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[A r] {3 d}^{8} {4 s}^{0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $[A r] {3 d}^{9} {4 s}^{0}$
Correct Electron Configuration for Copper (Cu)

Half-filled and fully filled subshell have got extra stability. Therefore, one of the $4 s^{2}$ electrons jumps to the $3 d^{9}$ . This give us the (correct) configuration of:

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{1}$

For the Cu+ ion we remove one electron from $4 s^{1}$ leaving us with: $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10}$

For the Cu2+ ion we remove a total of two electrons (one from the $4 s^{1}$ and one form the $3d^{10}) leaving us with

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{9}$

$C u^{2 +} = [A r] 4 s^{0} 3 d^{9}$

Hence, the correct option is $B$

Suggest Corrections

Similar questions

Q. What is the atomic number of the element with

M^{2 +}

ion having electronic configuration

[A r] 3 d^{8}

The $d$ electron configuration of $C r^{2 +}, M n^{2 +}, F e^{2 +}$ and $N i^{2 +}$ are $3 d^{4}, 3 d^{5}, 3 d^{6}$ and $3 d^{8}$ respectively. Which one of the following aqua complexes will exhibit the maximum paramagnetic behaviour?

The d - electron configurations of $M n^{2 +}, F e^{2 +}, C o^{3 +}, a n d N i^{2 +} a r e 3 d^{5}, 3 d^{6}, 3 d^{6}, 3 d^{8},$ respectively. Which of the following aqua complexes will exhibit the minimum paramagnetic behavior?

[A r] 3 d^{10} {4 s}^{1}

is electron shell configuration for:

Sir/Madam

In the structure of copper sulphate(CuSO4.5H2o),4 water molecules are coordinated and 1 is hydrogen bonded. The electronic configuration of Cu is [Ar]4s¹3d¹⁰. When the water molecules are sharing 8 electrons, it becomes 4s2 3d10 4p6 5s1. When cu becomes cu2+ion, the configuration becomes 4s2 3d10 4p5. But these 2 configurations aren't stable. Then why did cuso4.5h2o occurs at a reasonably good amount in nature. Kindly explain in "detail"?

Join BYJU'S Learning Program

The electronic configuration of Cu2+ ion is :

The electronic configuration of ${C u}^{2 +}$ ion is :