The electronic configuration of dipositive ion is [Kr] $4 d^{10} 5 s^{2} 5 p^{2}$ . Then atomic number of the element is .........

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Solution

The correct option is C 50
No. of electrons in the dipositive ion $= 36 + 10 + 2 + 2 = 50$
Atomic number of element = $50 + 2 = 52$

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The electronic configuration of dipositive ion is [Kr] 4d105s25p2. Then atomic number of the element is .........

The correct option is C 50No. of electrons in the dipositive ion =36+10+2+2=50Atomic number of element = 50+2=52

The electronic configuration of dipositive ion is [Kr] $4 d^{10} 5 s^{2} 5 p^{2}$ . Then atomic number of the element is .........

The correct option is C 50
No. of electrons in the dipositive ion $= 36 + 10 + 2 + 2 = 50$
Atomic number of element = $50 + 2 = 52$